5t^2-34=0

Solution for 5t^2-34=0 equation:

5t^2-34=0

a = 5; b = 0; c = -34;
Δ = b2-4ac
Δ = 02-4·5·(-34)
Δ = 680
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{680}=\sqrt{4*170}=\sqrt{4}*\sqrt{170}=2\sqrt{170}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{170}}{2*5}=\frac{0-2\sqrt{170}}{10}
=-\frac{2\sqrt{170}}{10}
=-\frac{\sqrt{170}}{5}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{170}}{2*5}=\frac{0+2\sqrt{170}}{10}
=\frac{2\sqrt{170}}{10}
=\frac{\sqrt{170}}{5}
$